#1**+1 **

3^5/27^3

3^5 / ( 3^3)^3

3^5 / 3^9

3^-4 for the right side

for the left side

(3^2)^y

so 3^(2y) = 3^(-4) can you finish from here (Hint: equate the exponents)

Guest Oct 29, 2021

#2**+2 **

Hi Guest,

\(9^y=\frac{3^5}{27^3}\)

\(\mbox {Calculate}\)

\(9^y=\frac{243}{19683}\)

\(\mbox {Now divide with 243}\)

\(9^y=\frac{1}{81}\)

\(\mbox {Write the expression in exponential form with the base of 3}\)

\({3}^{2y}=\frac{1}{81}\)

\(\mbox {Write the expression in exponential form with the base of 3}\)

\({3}^{2y}={3}^{-4}\)

\(\mbox {Since the bases are the same, set the exponents equal}\)

\(2y=-4\)

\(\mbox {Divide both sides of the equation by 2}\)

\(y=-2\)

Here's your answer.

!

Straight Oct 31, 2021